1z0-071 Training & Certification Get Latest Oracle PL/SQL Developer Certified Associate Updated on Oct 19, 2024
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Topics of ORACLE 1Z0-071 Certification Exam
Oracle 1Z0-071 Dumps covers the following topics of the ORACLE 1Z0-071 exam.
- SQL Fundamentals
- Oracle Architecture
- XML Fundamentals
- Data Integrity and Recovery
- SQL Language Features
- Data Management Concepts
Oracle 1z0-071 (Oracle Database SQL) Certification Exam is a popular certification exam designed for professionals who want to gain expertise in SQL programming language and demonstrate their skills in database management. 1z0-071 exam is designed to test the candidate's knowledge of SQL concepts, data retrieval, data manipulation, and data control language. It is an entry-level certification exam that is recognized globally, and passing it can help professionals to jumpstart their career in database management.
NEW QUESTION # 77
You need to allow user ANDREW to:
1. Modify the TITLE and ADDRESS columns of your CUSTOMERS table.
2. GRANT tha permission to other users.
Which statement will do this?
- A. GRANT UPDATE (title, address) ON customers TO andrew WITH GRANT OPTION:
- B. GRANT UPDATE ON customers. title, customers.address TO andrew WITH GRANT OPTION;
- C. GRANT UPDATE ON customers.title, customers.address TO andrew WITH ADMIN OPTION;
- D. GRANT UPDATE ON customers. title, customers.address TO andrew;
- E. GRANT UPDATE (title, address) ON customers TO andrew WITH ADMIN OPTION;
- F. GRANT UPDATE (title, address) ON customers TO andrew;
Answer: E
Explanation:
A: True. The GRANT statement with the WITH ADMIN OPTION allows the grantee to not only modify the specified columns but also to grant that permission to other users.
B: C, D, E, and F are incorrect because:
* B and C are incorrect due to the syntax; the correct syntax does not include the table name before each column when listing multiple columns in a GRANT statement.
* D and E do not include the necessary WITH GRANT OPTION which is required to enable the grantee to grant the permission to others.
* F is incorrect because the keyword WITH ADMIN OPTION should be used to allow the grantee to further grant the permission to others; WITH GRANT OPTION is correct in the context of object privileges.
NEW QUESTION # 78
View the Exhibit and examine PRODUCTS and ORDER_ITEMS tables.
You executed the following query to display PRODUCT_NAME and the number of times the product has been ordered:
SELECT p.product_name, i.item_cnt
FROM (SELECT product_id, COUNT (*) item_cnt
FROM order_items
GROUP BY product_id) i RIGHT OUTER JOIN products p
ON i.product_id = p.product_id;
What would happen when the above statement is executed?
- A. The statement would not execute because the GROUP BY clause cannot be used in the inline view.
- B. The statement would not execute because inline views and outer joins cannot be used together.
- C. The statement would execute successfully to produce the required output.
- D. The statement would not execute because the ITEM_CNT alias cannot be displayed in the outer query.
Answer: C
NEW QUESTION # 79
Examine these statements which execute successfully:
ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-YYYY HH24 MI: SS'
ALTER SESSION SET TIME_ ZONE = '-5:00';
SELECT DBTIMEZONE, SYSDATE FROM DUAL
Examine the result:
If LOCALTIMESTAMP was selected at the same time what would it return?
- A. 11-JUL-2019 11,00,00,000000AM -05:00
- B. 11-JUL-2019 6,00,00,00000000 AM - 05:00
- C. 11-JUL-2019 6,00,00,000000 AM
- D. 11-JUL-2019 11,00,00,00000000 AM
Answer: D
NEW QUESTION # 80
Which statement is true regarding the default behavior of the ORDER BY clause?
- A. NULLs are not included in the sort operation.
- B. In a character sort, the values are case-sensitive.
- C. Only columns that are specified in the SELECT list can be used in the ORDER BY clause.
- D. Column aliases can be used in the ORDER BY clause.
- E. Numeric values are displayed in descending order if they have decimal positions.
Answer: B
Explanation:
The ORDER BY clause performs case sensitive sorting with character values.
NEW QUESTION # 81
Examine the description of the ENPLYEES table:
Which two queries return all rows for employees whose salary is greater than the average salary in their department?
- A. SELECT"
FROM employees e1
WHERE salary >!
SELECT AVG (salary)
FROM employees e2
WHERE e1. Department _id = e2, department_ id - B. SELECT.
FROM
SELECT e.", AVG (salary) OVER (PARTITION BY department id) avg_ sal
FROM employees e
WHERE salary > avg_ sal; - C. SELECT "
FROM employees
WHERE salary > ANY
SELECT AVG (salary)
EROM employees
GROUP BY department_ id); - D. SELECT
FROM employees
WHERE salary > AVG (salary) OVER (PARTITION BY department _ id); - E. SELECT"
FROM employees
WHERE salary >
( SELECT AVG
(salary) FROM
employees
GROUP BY department _ id
Answer: A,B
NEW QUESTION # 82
Which statement is true regarding the INTERSECT operator?
- A. The names of columns in all SELECT statements must be identical.
- B. Reversing the order of the intersected tables alters the result.
- C. It ignores NULL values.
- D. The number of columns and data types must be identical for all SELECT statements in the query.
Answer: D
Explanation:
INTERSECT Returns only the rows that occur in both queries' result sets, sorting them and removing duplicates.
The columns in the queries that make up a compound query can have different names, but the output result set will use the names of the columns in the first query.
References:
http://oraclexpert.com/using-the-set-operators/
NEW QUESTION # 83
Examine the description of EMPLOYEES table:
Which three queries return all rows for which SALARY+COMMISSION is greate than 20000?
- A. SELECT * FROM employees WHERE NVL(salary+commission,0)>==20000;
- B. SELECT * FROM employees WHERE NVL2(salary)+commission,salary+commission,
- C. SELECT * FROM employees WHERE NVL(salary+commission,0)>=20000;
- D. SELECT * FROM employees WHERE salary+NULLF(commission,0)>=20000;
- E. SELECT * FROM employees WHERE salary+NVL2(commission,commission,0)>=20000;
- F. SELECT * FROM employees WHERE salary+NVL(commission,0)>=20000;
Answer: D,E,F
Explanation:
In Oracle Database 12c, when dealing with NULL values in arithmetic expressions, the functions NVL, NVL2
, and equivalent techniques using NULLIF or arithmetic operations with NULL can be crucial.
* Option A: SELECT * FROM employees WHERE salary + NULLIF(commission, 0) >= 20000;
* NULLIF(value1, value2) returns NULL if value1 is equal to value2, otherwise it returns value1.
In this case, if commission is NULL, it treats it as 0.
* This query correctly adds salary and commission (assuming 0 when commission is NULL) and checks if the total is at least 20000.
* Option B: SELECT * FROM employees WHERE salary + NVL2(commission, commission, 0) >=
20000;
* NVL2(expr1, expr2, expr3) returns expr2 if expr1 is not NULL; otherwise, it returns expr3.
Here, if commission is not NULL, it uses commission, otherwise 0.
* This condition correctly calculates salary + commission (assuming commission as 0 if it is NULL) and checks if the total is at least 20000.
* Option D: SELECT * FROM employees WHERE salary + NVL(commission, 0) >= 20000;
* NVL(expr1, expr2) returns expr2 if expr1 is NULL; otherwise, it returns expr1. This query treats commission as 0 if it is NULL.
* It correctly sums salary and commission and compares the result against 20000.
Options C, E, and F contain either syntax errors or logical errors in handling NULLs and comparisons.
NEW QUESTION # 84
Which two statements are true about the SET VERIFY ON command?
- A. It can be used in SQL Developer and SQL*Plus.
- B. It displays values for variables created by the DEFINE command.
- C. It displays values for variables used only in the WHERE clause of a query.
- D. It can be used only in SQL*plus.
- E. It displays values for variables prefixed with &&.
Answer: A,B
Explanation:
The SET VERIFY ON command is related to how SQL*Plus and SQL Developer display information about substitution variables:
* A. It displays values for variables created by the DEFINE command: When VERIFY is set to ON, SQL*Plus and SQL Developer will display the old and new values of a substitution variable when it is redefined using the DEFINE command or when a new value is provided for it during the session.
* B. It can be used in SQL Developer and SQL*Plus: While traditionally associated with SQL*Plus, the SET VERIFY command is also supported in SQL Developer, allowing you to control the display of substitution variable values in both environments.
References:
* Oracle SQL*Plus User's Guide and Reference, especially the section on the SET command and
* substitution variables.
NEW QUESTION # 85
View the Exhibit and examine the description of the tables.
You execute this SQL statement:
Which three statements are true?
- A. The statement will fail if a row already exists in the SALES table for product 23.
- B. The SALES table has five foreign keys.
- C. The statement will fail because a subquery may not be contained in a VALUES clause.
- D. A customer can exist in many countries.
- E. A product can have a different unit price at different times.
- F. The statement will execute successfully and a new row will be inserted into the SALES table.
Answer: B,D,F
NEW QUESTION # 86
Examine the structure of the BOOKS_TRANSACTIONS table:
Examine the SQL statement:
Which statement is true about the outcome?
- A. It displays details for members who have borrowed before today with RM as TRANSACTION_TYPE and the details for members A101 or A102.
- B. It displays details only for members who have borrowed before today with RM as TRANSACTION_TYPE.
- C. It displays details for only members A101 and A102 who have borrowed before today with RM TRANSACTION_TYPE.
- D. It displays details for members who have borrowed before today's date with either RM as TRANSACTION_TYPE or MEMBER_ID as A101 and A102.
Answer: A
NEW QUESTION # 87
You execute this query:
What is the result?
- A. It returns the date for the first Monday of the next month.
- B. It returns the date for the last Monday of the current month.
- C. It executes successfully but does not return any result.
- D. It generates an error.
Answer: A
NEW QUESTION # 88
View the exhibit and examine the structure of the PROMOTIONS table.
You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the 'INTERNET' category.
Which query would give you the required output?
- A. SELECT promo_name, promo_begin_date FROM promotionsWHERE
promo_begin_date> ANY (SELECT promo_begin_dateFROM promotionsWHERE
promo_category= 'INTERNET'); - B. SELECT promo_name, promo_begin_date FROM promotionsWHERE
promo_begin_date > ALL (SELECT promo_begin_dateFROM promotionsWHERE
promo_category = 'INTERNET'); - C. SELECT promo_name, promo_begin_date FROM promotionsWHERE
promo_begin_date> ALL (SELECT MAX (promo_begin_date)FROM promotions)
ANDpromo_category= 'INTERNET'; - D. SELECT promo_name, promo_begin_date FROM promotionsWHERE
promo_begin_date IN (SELECT promo_begin_dateFROM promotionsWHERE
promo_category= 'INTERNET');
Answer: B
NEW QUESTION # 89
View and Exhibit and examine the structure and data in the INVOICE table.
Which two statements are true regarding data type conversion in query expressions? (Choose two.)
- A. inv_no BETWEEN '101' AND '110' : uses implicit conversion
- B. inv_amt = '0255982' : requires explicit conversion
- C. inv_date > '01-02-2008' : uses implicit conversion
- D. inv_date = '15-february-2008' :uses implicit conversion
- E. CONCAT(inv_amt, inv_date) : requires explicit conversion
Answer: A,D
NEW QUESTION # 90
View the exhibit and examine the description of the PRODUCT_INFORMATION table.
Which SQL statement would retrieve from the table the number of products having LIST_PRICE as NULL?
- A. SELECT COUNT (list_price)FROM product_informationWHERE list_price is NULL
- B. SELECT COUNT (list_price)FROM product_informationWHERE list_price i= NULL
- C. SELECT COUNT (DISTINCT list_price)FROM product_informationWHERE list_price is NULL
- D. SELECT COUNT (NVL(list_price, 0))FROM product_informationWHERE list_price is NULL
Answer: D
NEW QUESTION # 91
View the Exhibit and examine the structure in the DEPARTMENTS tables. (Choose two.)
Examine this SQL statement:
SELECT department_id "DEPT_ID", department_name, 'b' FROM
departments
WHERE departments_id=90
UNION
SELECT department_id, department_name DEPT_NAME, 'a' FROM
departments
WHERE department_id=10
Which two ORDER BY clauses can be used to sort the output?
- A. ORDER BY DEPT_ID;
- B. ORDER BY 'b';
- C. ORDER BY DEPT_NAME;
- D. ORDER BY 3;
Answer: A,D
NEW QUESTION # 92
Examine the structure of the EMPLOYEEStable.
There is a parent/child relationship between EMPLOYEE_IDand MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_IDis 123.
Which query provides the correct output?
SELECT e.last_name, m.manager_id
- A. FROM employees e LEFT OUTER JOIN employees m
on (e.employee_id = m.manager_id)
WHERE e.employee_id = 123;
SELECT e.last_name, e.manager_id - B. FROM employees e RIGHT OUTER JOIN employees m
on (e.manager_id = m.employee_id)
AND e.employee_id = 123;
SELECT e.last_name, m.manager_id - C. FROM employees e LEFT OUTER JOIN employees m
on (e.manager_id = m.manager_id)
WHERE e.employee_id = 123; - D. FROM employees e RIGHT OUTER JOIN employees m
on (e.employee_id = m.employee_id)
WHERE e.employee_id = 123;
SELECT m.last_name, e.manager_id
Answer: C
Explanation:
Explanation
NEW QUESTION # 93
You execute these commands:
CREATE TABLE customers (customer id INTEGER, customer name VARCHAR2 (20));
INSERT INTO customers VALUES (1,'Custmoer1 ');
SAVEPOINT post insert;
INSERT INTO customers VALUES (2, 'Customer2 ');
<TODO>
SELECTCOUNT (*) FROM customers;
Which two, used independently, can replace <TODO> so the query retums 1?
- A. ROLLBACK;
- B. CONOIT TO SAVEPOINT post_ insert;
- C. COMMIT;
- D. ROLIBACK TO SAVEPOINT post_ insert;
- E. ROLLEBACK TO post_ insert;
Answer: D,E
NEW QUESTION # 94
The customers table has the following structure:
You need to write a query that does the following tasks:
1. Display the first name and tax amount of the customers. Tax is 5% of their credit limit.
2. Only those customers whose income level has a value should be considered.
3. Customers whose tax amount is null should not be considered.
Which statement accomplishes all the required tasks?
- A. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNTFROM customersWHERE cust_income_level IS NOT NULL ANDtax_amount IS NOT NULL;
- B. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNTFROM customersWHERE cust_income_level IS NOT NULL ANDcust_credit_limit IS NOT NULL;
- C. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNTFROM customersWHERE cust_income_level <> NULL ANDtax_amount <> NULL;
- D. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNTFROM customersWHERE (cust_income_level, tax_amount) IS NOT NULL;
Answer: B
NEW QUESTION # 95
An Oracle database server session has an uncommitted transaction in progress which updated 5000 rows in a table.
In which three situations does the transactions complete thereby committing the updates? (Choose three.)
- A. when the session logs out successfully
- B. when a DBA issues a successful SHUTDOWN IMMEDIATE statement and the user then issues a COMMIT
- C. when a COMMIT statement is issued by the same user from another session in the same database instance
- D. when a DBA issues a successful SHUTDOWN TRANSACTIONAL statement and the user then issues a COMMIT
- E. when a CREATE TABLE AS SELECT statement is executed unsuccessfully in the same session
- F. when a CREATE INDEX statement is executed successfully in the same session
Answer: A,B,F
NEW QUESTION # 96
View the Exhibit and examine the structure in the EMPLOYEES tables.
Evaluate the following SQL statement:
SELECT employee_id, department_id
FROM employees
WHERE department_id= 50 ORDER BY department_id
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=90
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=10;
What would be the outcome of the above SQL statement?
- A. The statement would not execute because the ORDER BY clause should appear only at the end of the SQL statement, that is, in the last SELECT statement.
- B. The statement would not execute because the positional notation instead of the column name should be used with the ORDER BY clause.
- C. The statement would execute successfully and display all the rows in the ascending order of DEPARTMENT_ID.
- D. The statement would execute successfully but it will ignore the ORDER BY clause and display the rows in random order.
Answer: A
NEW QUESTION # 97
You must write a query that prompts users for column names and conditions every time it is executed.
The user must be prompted only once for the table name.
Which statement achieves those objectives?
- A. SELECT &col1, '&col2'FROM &tableWHERE &&condition = '&cond';
- B. SELECT &col1, &col2FROM "&table"WHERE &condition = &cond;
- C. SELECT &col1, &col2FROM &&tableWHERE &condition = &cond;
- D. SELECT &col1, &col2FROM &&tableWHERE &condition = &&cond
Answer: C
NEW QUESTION # 98
Examine the structure of the DEPARTMENTS table.
You execute the following command:
Which two statements are true?
- A. Synonyms existing of the DEPARTMENTS table would have to be re-created.
- B. A new column, COUNTRY, can be added to the DEPARTMENTS table after executing the command.
- C. Views created in the DEPARTMENTS table that include the COUNTRY column are automatically modified and remain valid.
- D. Indexes created on the COUNTRY column exist until the DROP UNUSED COLUMNS command is executed.
- E. Unique key constraints defined on the COUNTRY column are removed.
Answer: B,E
NEW QUESTION # 99
Examine this SELECT statement and view the Exhibit to see its output:
SELECT constraints_name, constraints_type, search_condition, r_constraints_name, delete_rule, status, FROM user_constraints WHERE table_name = 'ORDERS'; Which two statements are true about the output? (Choose two.)
- A. In the second column, 'c' indicates a check constraint.
- B. The STATUS column indicates whether the table is currently in use.
- C. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.
- D. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
Answer: A,C
NEW QUESTION # 100
View the Exhibit and examine the description of the EMPLOYEEStable.
Evaluate the following SQL statement:
SELECT first_name, employee_id, NEXT_DAY(ADD_MONTHS(hire_date, 6), 1) "Review" FROM employees; The query was written to retrieve the FIRST_NAME, EMPLOYEE_ID,and review date for employees. The review date is the firsts Monday after the completion of six months of the hiring. The NLS_TERRITORY parameter is set to AMERICAin the session.
Which statement is true regarding this query?
- A. The query would not execute because the NEXT_DAYfunction accepts a string as argument.
- B. The query would execute but the output would give review dates that are Sundays.
- C. The query would not execute because date functions cannot be nested.
- D. The query would execute to give the desired output.
Answer: B
NEW QUESTION # 101
......
Exam Details
The Oracle 1Z0-071 exam is made up of 78 multiple-choice questions that are to be completed within the allocated timeframe of 120 minutes. The test is proctored by Pearson VUE, the official partner of Oracle. To schedule your session, you need to pay the fee of $245. But before that, you have to create an account with CertView, a web-based portal for all the Oracle certification activity. After you complete the exam, you will receive a notification from Oracle to your email address that your results are available on CertView. Log into the portal and click “See My New Exam Result Now” to find out whether you passed your 1Z0-071 test or not. To ace this exam, you need to give no less than 63% of correct answers.
It is strongly recommended that you undertake the relevant training before attempting the certification test. You can opt for one of the official courses offered by Oracle on its website. The examinees are encouraged to use Oracle training in combo with hands-on experience gained with the help of practical labs.
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Oracle PL/SQL Developer Certified Associate 1z0-071 Real Exam Questions and Answers FREE Updated: https://drive.google.com/open?id=1-ggLkeU_hkW23idBieqgdzsRkGbR39M9